CsBr crystallizes in a body centred cubic lattice. The unit edge cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro number being 6.02 × 10²³ mol^–1, the density of CsBr is

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8.50 g/cm³

0.425 g/cm³

42.5 g/cm³

4.25 g/cm³

answer is A.

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Detailed Solution

Density of CsBr = $\frac{Z \times M}{N_{A} \times a^{3}} = \frac{2 \times 213}{6.02 \times 10^{23} \times {(436.6 \times 10^{- 8})}^{3}} = 8.50 g / {cm}^{3}$

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