CsCl Crystallises in body centered cubic lattice. If ‘ a’ is its edge length then which of the following expression is correct?

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$r_{C s^{+}} + r_{C l^{-}} = \frac{3 a}{2}$

$r_{C s^{+}} + r_{C l^{-}} = 3 a$

$r_{C s^{+}} + r_{C l^{-}} = \frac{\sqrt{3} a}{2}$

$r_{C s^{+}} + r_{C l^{-}} = \sqrt{3} a$

answer is C.

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Detailed Solution

Relation between radius of cation, anion and edge length of the cube
$\begin{aligned} 2 r_{C s^{+}} + 2 r_{C l^{-}} = \sqrt{3} a \\ r_{C_{s}} + r_{C l^{-}} = \frac{\sqrt{3} a}{2} \end{aligned}$

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