${\mathrm{Cu}}^{2+}+2{\mathrm{e}}^{-}\to \mathrm{Cu};\log \left[{\mathrm{Cu}}^{2+}\right]\text{ vs E }$graph is of the type as shown in figure where OA = 0.34 V, then electrode potential of the half-cell of $\mathrm{Cu}\mid {\mathrm{Cu}}^{2+}\left(0.1\mathrm{M}\right)$ will be