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Q.

Cu2S+O2+H2O → CuSO4+CuO+H2


Which of the following is the correct balanced equation for the given equation?


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a

Cu2S+O2+3H2O→CuSO4+CuO+H2

b

Cu2S+2O2+H2O→CuSO4+CuO+H2

c

Cu2S+O2+1/2H2O→CuSO4+CuO+H2

d

Cu2S+1/2O2+H2O→CuSO4+CuO+H2 

answer is B.

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Detailed Solution

detailed_solution_thumbnail
In the given equation, the number of oxygen on both sides is not balanced. Hence multiply by 2 to O2 to balance oxygen atoms. After doing this, we get
Cu2S+2O2+H2O→CuSO4+CuO+H2
Balancing both sides with equal moles reactant and product.

Reactant

Product

Cu = 2

Cu = 2

S = 1

S = 1

O = 5

 

O = 5

H = 2

H = 2

 
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