CuO+H2→Cu+H2O is a balanced chemical equation, causing reduction of CuO. What volume of H2 at STP is required to reduce 7.95 gm of CuO to give Cu and H2O ?(Atomic weight of Cu = 63.5 U and Atomic weight of O = 16U)

1 mole of CuO – 1 mole of H279.5g of CuO – 22.4 Lt of H27.95g of CuO – 2.24 Lt of H2

CuO+H2→Cu+H2O is a balanced chemical equation, causing reduction of CuO. What volume of H2 at STP is required to reduce 7.95 gm of CuO to give Cu and H2O ?(Atomic weight of Cu = 63.5 U and Atomic weight of O = 16U)

1 mole of CuO – 1 mole of H279.5g of CuO – 22.4 Lt of H27.95g of CuO – 2.24 Lt of H2

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$CuO + H_{2} \to Cu + H_{2} O$ is a balanced chemical equation, causing reduction of CuO. What volume of H₂ at STP is required to reduce 7.95 gm of CuO to give Cu and H₂O ?
(Atomic weight of Cu = 63.5 U and Atomic weight of O = 16U)

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0.224 lit

22.4 lit

224 lit

2.24 lit

answer is C.

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Detailed Solution

1 mole of CuO – 1 mole of H₂
79.5g of CuO – 22.4 Lt of H₂
7.95g of CuO – 2.24 Lt of H₂

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CuO+H2→Cu+H2O is a balanced chemical equation, causing reduction of CuO. What volume of H2 at STP is required to reduce 7.95 gm of CuO to give Cu and H2O ?(Atomic weight of Cu = 63.5 U and Atomic weight of O = 16U)

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$CuO + H_{2} \to Cu + H_{2} O$ is a balanced chemical equation, causing reduction of CuO. What volume of H₂ at STP is required to reduce 7.95 gm of CuO to give Cu and H₂O ?
(Atomic weight of Cu = 63.5 U and Atomic weight of O = 16U)