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Current flowing through a 10 $Ω$ resistor varies with time according to the graph shown in figure, then

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total charge flown through the resistor is 6 coulomb.

maximum power dissipated in the resistor is 190 watt.

maximum power dissipated in the resistor is 150 watt.

total charge flown through the resistor is 60 coulomb.

answer is C.

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Detailed Solution

Total charge flown = $\int_{o}^{t} idt = area under i - t graph . = \frac{1}{2} \times 3 \times 4 coul = 6 coulomb$

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