Current in a circuit falls from 5.0 A to 0.0A in 0.1 s. If an average emf of 200V induced, give an estimate of the self–inductance of the circuit.

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Detailed Solution

$di = 5 - 0 = 5 A, di = 0 .1 s, e_{Avg} = 200 V$
Induced emf in the circuit :
$\begin{array}{l} e = - L \frac{di}{dt} = 200 \\ \Rightarrow L (\frac{5}{0 .1}) = 200 \\ \Rightarrow L = \frac{200}{50} = 4 H \end{array}$

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