Current through a circuit containing R and L or R and C or C and L is cos 100πt−3 . sin 100πt Amp.Voltage applied across the combination is 100 cos 100 πt volt. Then power consumed by the circuit is

(3)i=2cos 100πt.12− sin 100πt . 32 A=2 cos100πt+π3Aυ=100 cos 100 πt volt.∴ Power P = 22 1002 cos π3 watt =50W

Current through a circuit containing R and L or R and C or C and L is cos 100πt−3 . sin 100πt Amp.Voltage applied across the combination is 100 cos 100 πt volt. Then power consumed by the circuit is

(3)i=2cos 100πt.12− sin 100πt . 32 A=2 cos100πt+π3Aυ=100 cos 100 πt volt.∴ Power P = 22 1002 cos π3 watt =50W

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Current through a circuit containing R and L or R and C or C and L is
$(\cos 100 π t - \sqrt{3} . \sin 100 π t) A m p .$
Voltage applied across the combination is $100 \cos 100 π t v o l t .$ Then power consumed by the circuit is

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$50 \sqrt{3} W$

$25 \sqrt{3} W$

50 W

70 W

answer is C.

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Detailed Solution

(3)

$\begin{array}{l} i = 2 (\cos 100 π t . \frac{1}{2} - \sin 100 π t . \frac{\sqrt{3}}{2}) A = 2 \cos (100 π t + \frac{π}{3}) A \\ υ = 100 \cos 100 π t v o l t . \\ ∴ P o w e r P = (\frac{2}{\sqrt{2}}) (\frac{100}{\sqrt{2}}) \cos \frac{π}{3} w a t t = 50 W \end{array}$