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Curved mirrors produce images that are three times the size of objects placed 20 cm apart. For the image to be real, the focal length will be-

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$10 cm$

$15 cm$

$20 cm$

$40 cm$

answer is B.

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Detailed Solution

Magnification $= - v / u$

Then, $3 = - v / u$

$v = - 3 u = - 60 cm$

By mirror formula,

We get,

$\frac{1}{f} = \frac{1}{- 20} + \frac{1}{- 60}$

$\frac{1}{f} = \frac{3}{- 60} + \frac{1}{- 60}$

$\frac{1}{f} = \frac{4}{- 60} = \frac{1}{- 15}$

$f = - 15 cm$

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