CuS is dissolved in dil. ${HNO}_{3}$ . Balanced equation with correct products is

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$CuS + 2 H^{+} + 3 {NO}_{3}^{-} \overset{}{\to} Cu {({NO}_{3})}_{2} + H_{2} S + H_{2} O + {NO}_{2}$

$3 CuS + 8 H^{+} + 8 {NO}_{3}^{-} \overset{}{\to} 3 Cu {({NO}_{3})}_{2} + 3 S + 4 H_{2} O + 2 NO$

$3 CuS + 4 {NO}_{3}^{-} \overset{}{\to} Cu {({NO}_{3})}_{2} + 3 H_{2} S + H_{2} O$

None of the above in correct

answer is B.

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Detailed Solution

CuS (black ppt.) on boiling with ${HNO}_{3}$ results in the formation of colloidal S and blue colored solution of $Cu {({NO}_{3})}_{2}$ .

$CuS + {HNO}_{3} \to Cu {({NO}_{3})}_{2} + S + NO + H_{2} O Oxidation half reaction CuS + {HNO}_{3} \to Cu {({NO}_{3})}_{2} + S CuS + 2 {HNO}_{3} \to Cu {({NO}_{3})}_{2} + S + 2 H^{+} + 2 e^{-} - - - (1) Reduction half reaction {HNO}_{3} \to NO + H_{2} O {HNO}_{3} + 3 H^{+} + 3 e^{-} \to NO + 2 H_{2} O - - - (2) (1) \times 3 + (2) \times 2 \Rightarrow 3 CuS + 8 {HNO}_{3} \to 3 Cu {({NO}_{3})}_{2} + 3 S + 2 NO + 4 H_{2} O$