CuSO4·5H2O is blue in colour where as anhydrous CuSO4 is colourless why?

In CuSO4 .5H2O water acts as ligand as a result it causes crystal field spliting. Hence d-d transiton is possible thus CuSO4 .5H2O is coloured. In the anhydrous CuSO4 due to the absence of water, crystal field spliting is not possible hence it is colourless.

Book Online Demo

Check Your IQ

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

${CuSO}_{4} \cdot 5 H_{2} O$ is blue in colour where as anhydrous CuSO₄ is colourless why?

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 1.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

In CuSO₄ .5H₂O water acts as ligand as a result it causes crystal field spliting. Hence d-d transiton is possible thus CuSO₄ .5H₂O is coloured. In the anhydrous CuSO₄due to the absence of water, crystal field spliting is not possible hence it is colourless.

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th