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${CuSO}_{4} . 5 H_{2} O$ is represented as

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$[Cu {(H_{2} O)}_{4}] {SO}_{4} . H_{2} O$

$[Cu {(H_{2} O)}_{5}] {SO}_{4}$

$[Cu {(H_{2} O)}_{3} {SO}_{4}] . 2 H_{2} O$

answer is C.

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Detailed Solution

CuSO₄.5H₂O is represented as [Cu(H₂O )₄]SO₄.H₂O.
Here, 4 H₂O molecules are directly attached to the Cu atom, while one is present as water of crystallization.

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