$\mathrm{D}-(+)\text{ -Glucose }\stackrel{5{\left({\mathrm{CH}}_3\mathrm{CO}\right)}_2\mathrm{O}}{⟶}\mathrm{D}-(+)\text{ -glucose pentaacetate. }$

Which statement is true about glucose pentaacetate?

During acetylation of (+)-glucose, it is the C₁–OH of the hemiacetal that is acetylated and not the C₅–OH that forms the ring (cyclic structure). Since equilibrium with the open-chain aldehyde is prevented, the pentaacetate does not respond the aldehydic reactions.