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$D_{2} O$ is preferred to $H_{2} O$ , as a moderator, in nuclear reactors because

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$D_{2} O$ slows down fast neutrons better

$D_{2} O$ has high specific heat

$D_{2} O$ is cheaper

None of these

answer is D.

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Detailed Solution

$D_{2} O$ absorbs neutrons more than $H_{2} O$ and this decreases the number of neurons for the fission process.

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