Q.

DABC be a tetrahedran such that AD is perpendicular to the base ABC and  ABC=300 the volume of the tetrahedran is 18. If the value of AB+BC+AD  is minimum, then the length of AC is

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a

623

b

36+23

c

3623

d

62+3

answer is A.

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Detailed Solution

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V=13BaseArea.Height=48           (13.12.AB.BC.sin30×AO)=48            AO.AB.BC=216          AMGM          AB+BC+AO3=2163  = 6            AB+BC+AO=18         AB=BC=AO=6           AC2=AB2+BC22AB.BCos30           62+622.6.632        AC=72363 =623

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