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Q.

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively. From each can of paint 100 $m 2$ of area is painted. How many cans of paint will she need to paint the room?

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a

5

b

6

c

7

d

8

answer is A.

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Detailed Solution

It is given Length of wall is l is 15 m, breadth of wall b is 10 m, and height of wall h is 7 m.
It’s known that the total surface area of a cuboid = 2(lb + bh + lh)
It is given that the walls and ceiling are painted.
Therefore,
Area of hall to be painted is;

⇒ area of wall + area of ceiling . ⇒ 2(bh+hl)+lb ⇒ 2(10×7+7×15)+15×10 ⇒ 2(70+105)+150 ⇒ 350+150 ⇒ 500m 2

It is given that

area can be painted from each can.
Therefore, the number of cans required to paint

area

⇒ area of the hall to be painted area that can be painted from each can ⇒ 500100 ⇒ 5

Hence, number of cans of paint required is 5.
Hence option (1) is correct.

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