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David is observing his image in a plane mirror. The distance between the mirror and his image is $4 m$ . If he moves $1 m$ towards the mirror, then the distance between David and his image will be

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3 m

5 m

6 m

8 m

answer is C.

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Detailed Solution

The distance between David and his image will be

6 m .

The distance from the object to the mirror (object distance

D_{o}

) is the same as the distance from the image to the mirror (image distance

D_{I}

) in the case of a plane mirror.
Given the distance from the mirror to David’s image,

D_{I} = 4 m

Therefore,

D_{o} = D_{I} = 4 m

According to the question, David moves 1 m towards the mirror, then

{\Rightarrow D}_{o} = 4 - 1

{\Rightarrow D}_{o} = 3 m

Again,

D_{o} = D_{I} = 3 m

Therefore, the distance between David and his image is Distance

= D_{o} + D_{I}

= 3 + 3

= 6 m

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