ddx[(x+1)(x2+1)(x4+4)(x8+1)] =15xp+1−16xq(x−1)2 then p+q = ____

ddx[(x+1)(x2+1)(x4+1)(x8+1)(x+1)x−1]ddx[x16−1x−1]=(x−1)(16x15)−(x16−1)(x−1)2P=16, Q=15

ddx[(x+1)(x2+1)(x4+4)(x8+1)] =15xp+1−16xq(x−1)2 then p+q = ____

ddx[(x+1)(x2+1)(x4+1)(x8+1)(x+1)x−1]ddx[x16−1x−1]=(x−1)(16x15)−(x16−1)(x−1)2P=16, Q=15

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$\frac{d}{d x} [(x + 1) (x^{2} + 1) (x^{4} + 4) (x^{8} + 1)]$ $= \frac{15 x^{p} + 1 - 16 x^{q}}{{(x - 1)}^{2}}$ then p+q = ____

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$\frac{d}{d x} [\frac{(x + 1) (x^{2} + 1) (x^{4} + 1) (x^{8} + 1) (x + 1)}{x - 1}]$

$\frac{d}{d x} [\frac{x^{16} - 1}{x - 1}]$

$= \frac{(x - 1) (16 x^{15}) - (x^{16} - 1)}{{(x - 1)}^{2}}$

P=16, Q=15

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ddx[(x+1)(x2+1)(x4+4)(x8+1)] =15xp+1−16xq(x−1)2 then p+q = ____

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$\frac{d}{d x} [(x + 1) (x^{2} + 1) (x^{4} + 4) (x^{8} + 1)]$ $= \frac{15 x^{p} + 1 - 16 x^{q}}{{(x - 1)}^{2}}$ then p+q = ____