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$\frac{d}{d x} [x^{6} + x^{3} + 2 x] =$

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a

$6 x^{6} + 3 x^{3} + 2$

b

$6 x^{5} + 3 x^{2} + 2$

c

$6 x^{5} + 3 x + 2$

d

$5 x^{6} + 3 x^{4} + 2 x$

answer is B.

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Detailed Solution

$\frac{d}{d x} [x^{6} + x^{3} + 2 x] =$ $6 x^{5} + 3 x^{2} + 2$

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