De Broglie wavelength 'λ' of an ideal gas molecule at any given temperature is given as λ∝m−x×T−y . Where m = mass of one gas molecule; T = temperature (K). Given x + y =?

λ=h3mkT,λ∝m−1/2T−1/2The value of x + y is,x+y=-½ +-½ x+y=-1

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De Broglie wavelength ' $λ$ ' of an ideal gas molecule at any given temperature is given as $λ \propto m^{- x} \times T^{- y}$ . Where m = mass of one gas molecule; T = temperature (K).
Given x + y =?

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answer is 1.

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$λ = \frac{h}{\sqrt{3 mkT}},$

$λ \propto m^{- 1 / 2} T^{- 1 / 2}$

The value of x + y is,

x+y=-½ +-½

x+y=-1

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