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Q.

de-Broglie wavelength associated with an electron in the 3^rd orbit of He⁺ion is equal to

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a

1.59 ${πA}^{°}$

b

1.59 $π$ nm

c

1.59 $π$ pm

d

1.59 A⁰

answer is B.

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Detailed Solution

$λ = \frac{2 {πr}_{(n, Z)}}{n} = \frac{2 π}{n} \times r_{(1, H)} \times \frac{n^{2}}{Z}$

$λ = 2 π \times 0.53 \times \frac{3}{2}$ A⁰ = 1.59 $π$ A⁰

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