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Deacon’s process of manufacture of chlorine is represented by the equation

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${MnO}_{2} + HCl \to {MnCl}_{2} + {Cl}_{2} + H_{2} O$

${KMnO}_{4} + HCl \to KCl + {MnCl}_{2} + H_{2} O + {Cl}_{2}$

$HCl + O_{2} \overset{{CuCl}_{2}}{\to} {Cl}_{2} + H_{2} O$

$NaCl + {MnO}_{2} + H_{2} {SO}_{4} \to {Cl}_{2} + {MnCl}_{2} + {NaHSO}_{4} + H_{2} O$

answer is C.

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Detailed Solution

:Deacon's process is a method of preparation of chlorine by oxidation of HCl (g) by atmospheric oxygen in presence of CuCl₂ as catalyst at 725 K.

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