Q.

Decomposition of both A2(g) and B3(g)  follows 1st order kinetic as:
   A2(g)K12A(g)                              K1(hr1)=102e14000JRT
   B3(g)K23B(g)                             K2(hr1)=103e20000JRT
If one mole of each  A2(g) and B3(g) are taken in a 10 L evacuated flask and heated to some temperature so that they start decomposing at the same rate, determine total pressure (in atm) in the flask after 1.0 hr.

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answer is 8.

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Detailed Solution

102e14000RT=103e20000RT Solving
T= 313.42 K
    Rate constant   K1=K2=0.464  hr1
    K1t=lnn0(A2)n0(A2)n1n1=0.37    K2t=lnn0(B3)n0(B3)n2n2=0.37
Total moles of gases after 1.0 hr. = 1.37 + 1.74 = 3.11
P=nTRTV=3.11×0.0821×313.4210=8atm

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