Define the oxidation states of Mn in product of the given reaction
$3 K_{2} {MnO}_{4} + 2 H_{2} O + 4 {CO}_{2} ⟶ 2 X + Y + 4 {KHCO}_{3}$
If the oxidation state of Mn in product X and Y are $n_{1}$ and $n_{2}$ respectively. Then find out the value of $(n_{1} + n_{2})$ .

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answer is 11.

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Detailed Solution

The reaction is,

$3 K_{2} {MnO}_{4} + 2 H_{2} O + 4 {CO}_{2} ⟶ 2 {kMnO}_{4} + {MnO}_{2} + 4 {KHCO}_{3}$

The oxidation state of Mn in kmno4 is +7 whilw the oxidation state of Mn in MnO2 is +4.

Thus, the value of $(n_{1} + n_{2})$ ,

$n_{1} + n_{2} = 7 + 4 n_{1} + n_{2} = 11$

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