Densities of two gases neon and argon are in the ratio 1:2 and their temperatures are in the ratio 2:1 then the ratio of pressures of neon to that of argon is

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1:2

4:1

1 : 1

2:1

answer is B.

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Detailed Solution

Density of a gas is given by, $d = \frac{PM}{RT}$

$\frac{d_{Ne}}{d_{Ar}} = \frac{{(PM)}_{Ne} T_{Ar}}{{(PM)}_{Ar} T_{Ne}} \frac{1}{2} = \frac{P_{Ne}}{P_{Ar}} \times \frac{20}{40} \times \frac{2}{1} \frac{P_{Ne}}{P_{Ar}} = \frac{1}{2}$

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