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Q.

Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is

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a

0.44 mol kg-1

b

1.14 mol kg-1

c

3.28 mol kg-1

d

2.28 mol kg-1

answer is B.

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Detailed Solution

mass of 1.0 L solution = 1020 g
mass of H2O in 1.0 L solution =1020-2.05×60=897 g

⇒  Molality=2.05897×1000=2.28 molal

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