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Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is

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a
3.28 mol kg-1
b
2.28 mol kg-1
c
0.44 mol kg-1
d
1.14 mol kg-1

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detailed solution

Correct option is B

mass of 1.0 L solution = 1020 g
mass of H2O in 1.0 L solution =1020-2.05×60=897 g

  Molality=2.05897×1000=2.28 molal

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