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Density of gas ‘A’ (molar mass=4 g) present in a closed vessel at 27°C and 16 atm is 2.6 g/litre. Density of unknown gas present in another closed vessel at 300K and 1 atm is 2.6 g/ litre. Molar mass of unknown gas is

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64 g

32 g

64 u

32 u

answer is A.

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Detailed Solution

$\begin{array}{l} d = \frac{PM}{RT} \\ given \\ d_{A} = d_{X} \\ T_{A} = T_{X} \\ ' R' is always a constant \\ ∴ PM = constant \\ \frac{M_{X}}{M_{A}} = \frac{P_{A}}{P_{X}} \\ M_{X} = \frac{16}{1} \times 4 = 64 grams \end{array}$

Note ; Molar mass is the mass of one mole of gas expressed in grams.

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