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Q.

Density of ice is $ρ$ and that of water is $σ$ . If the decrease in the volume of ice is D due to melt of ice, the mass of ice is

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a

$D (\frac{ρ}{ρ + σ})$

b

$D (\frac{ρ σ}{σ - ρ})$

c

$D (\frac{σ}{ρ + σ})$

d

$D (\frac{ρ σ}{ρ - σ})$

answer is C.

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Detailed Solution

$D = \frac{M}{ρ} - \frac{M}{σ} \Rightarrow M = D (\frac{ρ σ}{σ - ρ})$

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