Density of methanol is 0.0008 kg L^-1. What volume of methanol in ml is required to prepare 2.5 L of a 0.25 M solution of methanol?

Mass of methanol present in given solution = 2.5 x 0.25 x 32 = 20 gm / L = 20 x 10^-3 kg/L

density = $\frac{\mathrm{mass} }{\mathrm{volume}}$

volume = $\frac{20\times {10}^{-3}}{0.0008}$ = 25