Q.

Derive the equations s=ut+12t2 using graphical method.

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Detailed Solution

Consider a body moves with an initial velocity = u
Uniform acceleration = a
Final velocity = v ; Time taken = t

For this motion v – t graph is plotted as,
Question Image
S = Area of OABD
S= Area of □OACD+ Area of ABC
S=(OA×OD)+12(AC×BC)
S=(u×t)+12[t×(vu)]          [vu=at]
S=ut+12[t×at]S=ut+12at2

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