Q.

Derive the relation between Kp and Kc for the following reactions.
 i) 2HI(g) H2(g)+I2(g)
 ii) N2(g)+3H2(g) 2NH3(g)
 iii) 2SO2(g)+O2(g)  2SO3(g)
 iv) CaCO3(s) CaO(s)+CO2(g)

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Detailed Solution

In chemical equilibrium involving gases, the equilibrium constants Kp and Kc are related by the equation:

Kp = Kc (RT)Δn

Where:

  • Kp = equilibrium constant in terms of partial pressures
  • Kc = equilibrium constant in terms of concentrations
  • R = universal gas constant
  • T = temperature in Kelvin
  • Δn = change in the number of moles of gas, calculated as nproducts − nreactants

i) Reaction: 2 HI (g) ⇌ H2 (g) + I2 (g)

For this reaction, the change in the number of moles (Δn) is calculated as:

Δn = nproducts − nreactants = (1 + 1) − 2 = 0

Substituting into the Kp and Kc relation formula:

Kp = Kc (RT)0

Since any number raised to the power of 0 is 1:

Kp = Kc

ii) Reaction: N2 (g) + 3 H2 (g) ⇌ 2 NH3 (g)

For this reaction, the change in the number of moles (Δn) is:

Δn = nproducts − nreactants = 2 − (1 + 3) = −2

Substituting into the Kp and Kc relation formula:

Kp = Kc (RT)−2

Since (RT)−2 is less than 1:

Kp < Kc

iii) Reaction: 2 SO2 (g) + O2 (g) ⇌ 2 SO3 (g)

For this reaction, the change in the number of moles (Δn) is:

Δn = nproducts − nreactants = 2 − (2 + 1) = −1

Substituting into the Kp and Kc relation formula:

Kp = Kc (RT)−1

Since (RT)−1 is less than 1:

Kp < Kc

iv) Reaction: CaCO3 (s) ⇌ CaO (s) + CO2 (g)

For this reaction, the change in the number of moles (Δn) is:

Δn = nproducts − nreactants = 1 − 0 = 1

Substituting into the Kp and Kc relation formula:

Kp = Kc (RT)1

Since (RT)1 is greater than 1:

Kp > Kc

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