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Determine D and E in the given reaction series.

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D=NH₃, E=N₂

D=N₂, E=NH₃

D=H₂, E=NH₃

D=NH₃, E=H₂

answer is A.

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Detailed Solution

$4 Mg + air \overset{Ignition}{\to} \underset{B}{MgO} + \underset{A}{{Mg}_{3} N_{2}}$

$\underset{A}{{Mg}_{3} N_{2}} + 6 HCl \to \underset{D}{2 {NH}_{3} ↑} + \underset{C}{3 {MgCl}_{2}}$

$3 CuO + 2 {NH}_{3} \to 3 Cu + \underset{E}{N_{2} ↑} + 3 H_{2} O$

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