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Q.

Determine graphically the vertices of the triangle, the equations of whose side are given below:


y=x,y=0 and 3x+3y=10 .


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a

(0,0),(103,0),(53,53)

b

(0,0),(173,0),(53,53)

c

(0,0),(143,0),(53,53)

d

(0,0),(103,0),(53,83)  

answer is A.

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Detailed Solution

It is given that three lines ,
y=x,y=0 and 3x+3y=10.
We have,
y=x
Substituting the value of x to get the value of y,

x

0

2

y

0

2

We have,
3y=10-3x
Substituting the value of x to get the value of y,

x

0

103

y

103

0

According to the given data the figure has been drawn below,
Question ImageAs shown in the graph, to find vertices of required triangle,
We can find intersection of lines 1 and 3.
 3x+3y=10 and y=x  which is (53,53) .
Now the intersection of y=0 and 3x+3y=10 is (103,0), and
y=x and y=0 which is origin (0,0).
So the correct option is 1.
 
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