Determine the heat of reaction for this processFeO(s)+Fe2O3(s)⟶Fe3O4(s)Given information :2Fe(s)+O2(g)⟶2FeO(s) ΔH∘=−544.0kJ4Fe(s)+3O2(g)→2Fe2O3(s) ΔH∘=−1648.4kJFe3O4(s)⟶3Fe(s)+2O2(g) ΔH∘=+1118.4kJ

2Fe(s)+O(g)→2Fe(s)+O2g; ΔH∘=−544kJ2Fe2O3(s)⟶4Fe(s)+3O2(g)ΔH∘=+1648kJ6Fe(s)+4O2(g)→2Fe2O3(s);ΔH∘=−2×1118.4kJOn adding 2FeO(s)+2Fe2O3(s)→2Fe3O4(s);ΔH∘=−44.4kJ2FeO(s)+2Fe2O3(s)⟶2Fe3O4(s);ΔH∘=−22.2kJΔH=−1118.4+1648.42+5442 =−22.2kJ

Determine the heat of reaction for this processFeO(s)+Fe2O3(s)⟶Fe3O4(s)Given information :2Fe(s)+O2(g)⟶2FeO(s) ΔH∘=−544.0kJ4Fe(s)+3O2(g)→2Fe2O3(s) ΔH∘=−1648.4kJFe3O4(s)⟶3Fe(s)+2O2(g) ΔH∘=+1118.4kJ

2Fe(s)+O(g)→2Fe(s)+O2g; ΔH∘=−544kJ2Fe2O3(s)⟶4Fe(s)+3O2(g)ΔH∘=+1648kJ6Fe(s)+4O2(g)→2Fe2O3(s);ΔH∘=−2×1118.4kJOn adding 2FeO(s)+2Fe2O3(s)→2Fe3O4(s);ΔH∘=−44.4kJ2FeO(s)+2Fe2O3(s)⟶2Fe3O4(s);ΔH∘=−22.2kJΔH=−1118.4+1648.42+5442 =−22.2kJ

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Determine the heat of reaction for this process
$FeO (s) + {Fe}_{2} O_{3} (s) ⟶ {Fe}_{3} O_{4} (s)$
Given information :
$\begin{array}{l} 2 Fe (s) + O_{2} (g) ⟶ 2 FeO (s) {ΔH}^{\circ} = - 544 .0 kJ \\ 4 Fe (s) + 3 O_{2} (g) \to 2 {Fe}_{2} O_{3} (s) {ΔH}^{\circ} = - 1648 .4 kJ \\ {Fe}_{3} O_{4} (s) ⟶ 3 Fe (s) + 2 O_{2} (g) {ΔH}^{\circ} = + 1118 .4 kJ \end{array}$

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+249-8 kJ

- 22.2 kJ

-1074.0 kJ

+2214.6 kJ

answer is B.

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Detailed Solution

$2 Fe (s) + O (g) \to 2 Fe (s) + O_{2}) g); {ΔH}^{\circ} = - 544 kJ$

$\begin{array}{l} 2 {Fe}_{2} O_{3} (s) ⟶ 4 Fe (s) + 3 O_{2} (g) {ΔH}^{\circ} = + 1648 kJ \\ 6 Fe (s) + 4 O_{2} (g) \to 2 {Fe}_{2} O_{3} (s); {ΔH}^{\circ} = - 2 \times 1118 .4 kJ \end{array}$

On adding

$2 FeO (s) + 2 {Fe}_{2} O_{3} (s) \to 2 {Fe}_{3} O_{4} (s); {ΔH}^{\circ} = - 44 .4 kJ$ $2 FeO (s) + 2 {Fe}_{2} O_{3} (s) ⟶ 2 {Fe}_{3} O_{4} (s); {ΔH}^{\circ} = - 22.2 kJ$