Determine the median of the following data.

Marks (out of 60.)	32	27	26	24	23	21
Number of students	6	4	7	9	16	2

 

To calculate the median from the following interval data, we must first compute the cumulative frequencies.

Because the class widths are unequal in this case, we don't need to adjust the interval frequencies.

Total number of students $=6+4+7+9+16+2=44$

Since, the number of students is even, the median will be mean of $\left(\frac{n^{\text{n }}}{2}\right)$ and $\left(\frac{\mathrm{n}+2^{\text{th }}}{2}\right)$ number

Median = Mean of ${\left(\frac{44}{2}\right)}^{\text{th }}$ and ${\left(\frac{44+2}{2}\right)}^{\text{th }}$

Here, ${22}^{\text{nd }}$ and ${23}^{\text{rd }}$ number is 24 if arranged in ascending order.

Hence, median $=\frac{24+24}{2}=24$