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Q.

Determine the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8, 15, and 21.


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a

105200

b

104200

c

106200

d

109200 

answer is D.

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Detailed Solution

To be divisible by 8,15 and 21 a number should be divided by lowest common factor of these numbers.
Here, factors of the given numbers,
8=2×2×2
15=3×5
21=3×7
So, the lowest common factor,
LCM=2×2×2×3×5×7
LCM=840
Now, we get 800 as reminder when 110000 is divided by 840.
So, the number near 110000 but greater than 100000 and divisible by 8,15 and 21,
=110000-840
=109200
Hence option 4 is correct.
 
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