Q.

Determine the value of the first ionization potential of potassium atom if H for the given gaseous phase reaction: 

K(g)+F(g)K+(g)+F(g)

is 0.82 eV and the first electron affinity of F is -3.48 eV.

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a

2.15 eV

b

4.30 eV

c

1.0 eV

d

-4.3 eV

answer is B.

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Detailed Solution

Relation between the change in enthalpy of a reaction, H, ionization energy and electron affinity is:

H=Ionization energy+Electron affinity

Substitute the given values.

0.82 eV=Ionization energy+(-3.48 eV)Ionization energy=4.30 eV

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