Determine which of the following reactions at constant pressure represent surroundings that do work on the system environment :

(P) $4{\mathrm{NH}}_3\left(g\right)+7{\mathrm{O}}_2\left(g\right)⟶4{\mathrm{NO}}_2\left(g\right)+6{\mathrm{H}}_2\mathrm{O}\left(g\right)$

(Q) $\begin{array}{r}\mathrm{CO}\left(g\right)+2{\mathrm{H}}_2\left(g\right)⟶{\mathrm{CH}}_3\mathrm{OH}\left(l\right)\end{array}$

(R)$\begin{array}{l}\mathrm{C}(s,\text{ graphite })+{\mathrm{H}}_2\mathrm{O}\left(\mathrm{g}\right)⟶\mathrm{CO}\left(g\right)+{\mathrm{H}}_2\left(g\right)\end{array}$

(S) ${\mathrm{H}}_2\mathrm{O}\left(s\right)⟶{\mathrm{H}}_2\mathrm{O}\left(l\right)$

When work is done on the system, it is considered as negative.

In the reaction of option P, 11 Vols of reagents form 10 vols of product. In this, volume reduces and work done is negative.

In the reaction of option Q, 3 Vols reagents form 1 vols of product. In this, volume reduces and work done is negative.

In the reaction of option R, 2 Vols reagents form 2 vols of product. No change in surrounding.

In the reaction of option S, volume changed and work done is negative.

Here, P, Q, S are correct according to the given statement.