Diagram of a cyclic process $A B C A$ is as shown in fig. Choose the correct alternative.

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$∆ {Q_{}}_{A \to B}$ is negative

$△ Q_{B \to C}$ is positive

$∆ U_{C \to A}$ is negative

$∆ W_{C A B}$ is negative

answer is A, B, D.

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Detailed Solution

During process $A$ and $B$ , pressure and volume both are decreasing. Therefore, temperature and hence internal energy of the gas will decrease $(△ U \propto △ T) o r ∆ V_{A} \to_{B} = n e g a t i v e .$ Further, $∆ W_{A} \to_{B}$ is negative.

In process $B$ to $C$ , pressure of the gas is constant while volume is increasing. Hence, temperature should increase or $∆ U_{B} \to_{C} =$ positive. During $C$ to $A$ volume is constant while pressure is increasing. Therefore, temperature and hence internal energy of the gas should increase of $∆ U_{C} \to_{A} =$ positive.