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Diagram shows a bird B and a fish F moving in two different medium of refractive index 1.5 and 2 with speed 10 m/s and 5 m/s respectively. At the given instant bird is located at height 5m above the interface while fish is located at depth of 10 m. List-I indicates various parameters while List-II gives its values. Match them correctly :-

Column-I

Column-II
(A)
Separation of fish as observed by bird
(p)
$\frac{50}{3} unit$
(B)
Separation of bird as observed by fish
(q)
$12.5 unit$
(C)
Speed of fish as observed by bird
(r)
$\frac{10}{3} unit$
(D)
Speed of bird as observed by fish
(s)
$2.5 unit$
The correct option is:

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(I)-(Q) (II)-(P) (III)-(S) (IV)-(R)

(I)-(R) (II)-(Q) (III)-(P) (IV)-(S)

(I)-(S) (II)-(P) (III)-(Q) (IV)-(R)

(I)-(P) (II)-(Q) (III)-(R) (IV)-(S)

answer is B.

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Detailed Solution

(I) $5 + 10 \times \frac{1.5}{2} = 12.5$
Hence I – Q
(II) $10 + 5 \times \frac{2}{1.5} = 10 + \frac{20}{3} = \frac{50}{3}$
Hence II – P
(III) $V = 5 - 10 \times \frac{1.5}{2} = - 2.5 \Rightarrow 2.5$
Hence III – S
(IV) $- 10 + 5 \times \frac{4}{3} = \frac{- 10}{3}$
Hence IV – R

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