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Diatomic gas at pressure ‘P’ and volume ‘V’ is compressed adiabatically to 1/32 times the orginal volume. Then the final pressure is

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P/32

32 P

128 P

P/128

answer is C.

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Detailed Solution

${P_1}v_1^gamma = {P_2}v_2^gammaRightarrow {P_2} = P{left( {frac{{{v_1}}}{{{v_2}}}} right)^gamma }Rightarrow {P_2} = P{left( {32} right)^{7/5}}$

$= p{({2^5})^{7/5}} = 128P$

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