Diborane (B₂H₆) reacts independently with O₂ and H₂O to produce respectively:

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B₂O₃and H₃BO₃

H₃BO₃ and B₂O

HBO₂ and H₃BO₃

B₂O₃ and [BH₄]^-

answer is A.

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Detailed Solution

$\begin{array}{l} B_{2} H_{6} + 3 O_{2} ⟶ B_{2} O_{3} + 3 H_{2} O : ΔH = - 1976 kJ {mol}^{- 1} \\ B_{2} H_{6} + 6 H_{2} O ⟶ 2 H_{3} {BO}_{3} + 6 H_{2} \end{array}$

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