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Q.

Diborane $(B_{2} H_{6})$ reacts independently with $O_{2}$ and $H_{2} O$ to produce, respectively

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a

$H_{3} {BO}_{3} {and B}_{2} O_{3}$

b

$B_{2} O_{3} {and H}_{3} {BO}_{3}$

c

${HBO}_{2} {and H}_{3} {BO}_{3}$

d

$B_{2} O_{3} and$ ${[{BH}_{4}]}^{-}$

answer is B.

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Detailed Solution

$B_{2} H_{6} + 3 O_{2} \to_{}^{} B_{2} O_{3} + 3 H_{2} O + heat$

$B_{2} H_{6} + 6 H_{2} O \to_{}^{} 2 H_{3} {BO}_{3} + 6 H_{2}$

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Diborane (B2H6)reacts independently with O2and H2O to produce, respectively