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Diborane reacts separately with $O_{2}$ and $H_{2} O$ to produce respectively

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$H B O_{2} and H_{3} B O_{3}$

$B_{2} O_{3} and H_{3} B O_{3}$

$B_{2} O_{3} and B H_{4}^{-}$

$H_{3} B O_{3} and B_{2} O_{3}$

answer is B.

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Detailed Solution

$B_{2} H_{6} + 3 O_{2} \overset{}{\to} B_{2} O_{3} + 3 H_{2} O$

$B_{2} H_{6} + 6 H_{2} O \overset{}{\to} 2 H_{3} B O_{3} + 6 H_{2}$

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