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Q.

Diborane reacts with ammonia at high temperature ( $200 ° c$ ) to form

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a

$H_{3} {BO}_{3}, N_{2}$

b

$B_{3} N_{3} H_{6}, H_{2}$

c

$B_{2} H_{6} . 2 {NH}_{3}$

d

$B_{3} N_{3} H_{6}, N_{2}$

answer is B.

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Detailed Solution

$3 B_{2} H_{6} + 6 {NH}_{3} \overset{200 ° c}{\to} 2 B_{3} N_{3} H_{6} + 12 H_{2}$

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Diborane reacts with ammonia at high temperature (200°c) to form