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Diborane reacts independently with $O_{2}$ and $H_{2} O$ to produce, respectively

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${HBO}_{2}$ and $H_{3} {BO}_{3}$

$H_{3} {BO}_{3}$ and $B_{2} O_{3}$

$B_{2} O_{3}$ and $H_{3} {BO}_{3}$

$B_{2} O_{3}$ and ${[{BH}_{4}]}^{-}$

answer is C.

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Detailed Solution

Diborane reacts with water to form boric acid and hydrogen gas.

$B_{2} H_{6} + 3 H_{2} O \to 2 H_{3} {BO}_{3} + 3 H_{2}$

Diborane reacts with oxygen to form boron trioxide and water.

$B_{2} H_{6} + 3 O_{2} \to B_{2} O_{3} + 3 H_{2} O$

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