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Q.

Dichromate ion is treated with base. The oxidation number of Cr in the product formed is ______.

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answer is 6.

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Detailed Solution

${Cr}_{2} O_{7}^{- 2} + 2 {OH}^{-} \to 2 {CrO}_{4}^{- 2} + H_{2} O$

$Cr {O_{4}}^{2 -}$

X +4 (-2) =-2

X -8 =-2

X =+6

Hence, the oxidation of Cr = 6.

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