Diethyl ether when heated to 3500C with Al2O3 forms

2C2H5−O−C2H5→3500CAl2O32C2H4+H2O

2C2H5−O−C2H5→3500CAl2O32C2H4+H2O

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Diethyl ether when heated to 350⁰C with ${Al}_{2} O_{3}$ forms

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Ethane

Ethene

Ethyne

Ethyl alcohol

answer is B.

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$2 C_{2} H_{5} - O - C_{2} H_{5} \to_{35 0^{0} C}^{A l_{2} O_{3}} 2 C_{2} H_{4} + H_{2} O$

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