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Different combination of 3 resistors of equal resistance R are shown in the figures. The increasing order for power dissipation is:

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$P_{C} < P_{B} < P_{A} < P_{D}$

$P_{C} < P_{D} < P_{A} < P_{B}$

$P_{B} < P_{C} < P_{D} < P_{A}$

$P_{A} < P_{B} < P_{C} < P_{D}$

answer is A.

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Detailed Solution

$R_{1} = \frac{3 R}{2} = 1.5 R$

$R_{2} = \frac{2 R . R}{2 R + R} = \frac{2 R}{3} = 0.6 R$

$R_{3} = \frac{R}{3} = 0.3 R$

$R_{4} = 3 R$

$As current is same P \propto R$

$P_{C} < P_{B} < P_{A} < P_{D}$

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