Differential coefficient of tan-12x1-x2 with respect to sin-12x1+x2 will be

u=2tan−1x,v=2tan−1x, Hence, dudv=1

Differential coefficient of tan-12x1-x2 with respect to sin-12x1+x2 will be

u=2tan−1x,v=2tan−1x, Hence, dudv=1

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$D i f f e r e n t i a l c o e f f i c i e n t o f$ $\tan^{- 1} \frac{2 x}{1 - x^{2}} with respect to$ $\sin^{- 1} \frac{2 x}{1 + x^{2}} will be$

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$- \frac{1}{2}$

answer is A.

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$u = 2 \tan^{- 1} x, v = 2 \tan^{- 1} x, Hence, \frac{d u}{d v} = 1$

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Differential coefficient of tan-12x1-x2 with respect to sin-12x1+x2 will be

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$D i f f e r e n t i a l c o e f f i c i e n t o f$ $\tan^{- 1} \frac{2 x}{1 - x^{2}} with respect to$ $\sin^{- 1} \frac{2 x}{1 + x^{2}} will be$